X^2-27x+5=0

Solution for X^2-27x+5=0 equation:

X^2-27X+5=0

a = 1; b = -27; c = +5;
Δ = b2-4ac
Δ = -272-4·1·5
Δ = 709
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{709}}{2*1}=\frac{27-\sqrt{709}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{709}}{2*1}=\frac{27+\sqrt{709}}{2}
$